An element, $Y$, takes part in the sequence shown below. When $Y$ burns in $\text{O}_2$, a white solid is formed. This white solid reacts with $\text{HCl(aq)}$ to produce a solution. When $\text{NaOH(aq)}$ is added, a white precipitate is formed, and this precipitate then dissolves in excess $\text{NaOH(aq)}$ to form a solution. Which element could $Y$ be?
- A$\text{Na}$
- B$\text{Mg}$
- C$\text{Al}$
- D$\text{P}$