The table lists the successive ionisation energies of element X. Ionisation energies / $\text{kJ mol}^{-1}$: $1\text{st}: 950$, $2\text{nd}: 1800$, $3\text{rd}: 2700$, $4\text{th}: 4800$, $5\text{th}: 6000$, $6\text{th}: 12300$. What might be the formula of the chloride of X?
- A$\text{XCl}$
- B$\text{XCl}_2$
- C$\text{XCl}_3$
- D$\text{XCl}_4$