Chemistry 9701 · AS & A Level · States of matter

States of matter — practice question

A single atom of each of the four elements H, C, N and O can combine in more than one arrangement. Two illustrations are cyanic acid, HOCN, and isocyanic acid, HNCO. In each case the atoms are linked in the same sequence as they are written.
(a(i))[3]

Draw dot-and-cross diagrams for these two acids, showing only outer-shell electrons, for HOCN(cyanic acid) and HNCO (isocyanic acid).

(a(ii))[1]

Suggest the bond-angle values for HNC and NCO in isocyanic acid.

(a(iii))[1]

Suggest which acid, cyanic or isocyanic, has the shorter $\text{C-N}$ bond length. Explain your answer.

(b(i))[2]

Isocyanic acid is a weak acid. $\text{HNCO} \rightleftharpoons \text{H}^+ + \text{NCO}^- \quad K_a = 1.2 \times 10^{-4}\,\text{mol dm}^{-3}$. Calculate the pH of a $0.10\,\text{mol dm}^{-3}$ solution of isocyanic acid.

(b(ii))[1]

Sodium cyanate, $\text{NaNCO}$, is used in the manufacture of isocyanic acid. Sodium cyanate is made commercially by reacting urea, $(\text{NH}_2)_2\text{CO}$, with sodium carbonate. The other products in this reaction are carbon dioxide, ammonia and steam. Write an equation for making $\text{NaNCO}$ by this route.

(c(i))[2]

Barium hydroxide, $\text{Ba(OH)}_2$, is completely ionised in aqueous solution. When $30.0\,\text{cm}^3$ of $0.100\,\text{mol dm}^{-3}$ $\text{Ba(OH)}_2$ is added to $20.0\,\text{cm}^3$ of $0.100\,\text{mol dm}^{-3}$ isocyanic acid, the pH is measured. Calculate the $[\text{OH}^-]$ at the end of the addition.

(c(ii))[2]

Use your answer to (i) to find $[\text{H}^+]$ and the pH of the solution at the end of the addition.

(c(iii))[3]

On the axes below, sketch the change in pH as a total of $30.0\,\text{cm}^3$ of $0.100\,\text{mol dm}^{-3}$ $\text{Ba(OH)}_2$ is added to $20.0\,\text{cm}^3$ of $0.100\,\text{mol dm}^{-3}$ isocyanic acid.

(d(i))[2]

The cyanate ion, $\text{NCO}^-$, can act as a monodentate ligand. State what is meant by the terms monodentate and ligand.

(d(ii))[2]

Silver ions, $\text{Ag}^+$, react with cyanate ions to form a linear complex. Suggest the formula of this complex, including its charge.

(e(i))[1]

When heated with $\text{HCl(aq)}$, organic isocyanates, RNCO, are hydrolysed to the amine salt, $\text{RNH}_3\text{Cl}$, and $\text{CO}_2$. $\text{RNCO} + \text{H}_2\text{O} + \text{HCl} \rightarrow \text{RNH}_3\text{Cl} + \text{CO}_2$ A $1.00\,\text{g}$ sample of an organic isocyanate, RNCO, was treated in this way, and the $\text{CO}_2$ produced was absorbed in an excess of aqueous $\text{Ba(OH)}_2$ according to the equation shown. The solid $\text{BaCO}_3$ formed weighed $1.66\,\text{g}$. $\text{Ba(OH)}_2\text{(aq)} + \text{CO}_2\text{(g)} \rightarrow \text{BaCO}_3\text{(s)} + \text{H}_2\text{O(l)}$ Calculate the number of moles of $\text{BaCO}_3$ produced.

(e(ii))[1]

Hence calculate the $M_r$ of the organic isocyanate RNCO.

(e(iii))[1]

The R group in RNCO and $\text{RNH}_3\text{Cl}$ contains only carbon and hydrogen. Use your $M_r$ value from (ii) to suggest the molecular formula of the organic isocyanate RNCO.

(e(iv))[1]

Suggest a possible structure of the amine $\text{RNH}_2$, which forms the amine salt, $\text{RNH}_3\text{Cl}$.

(c(iv))[1]

Suggest a possible structure of the amine RNH$_2$, which forms the amine salt, RNH$_3$Cl.

Worked solution & mark scheme

This 24-mark question has a full step-by-step worked solution and mark scheme. One marking point: Accurate dot-and-cross structures

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