Chemistry 9701 · AS & A Level · States of matter

States of matter — practice question

(a)[1]

Although fluorine is far more electronegative than silicon and sulfur, $\text{SF}_4$ has an overall dipole but $\text{SiF}_4$ does not. Suggest a reason for this difference.

(b)[2]

Predict whether each of the following molecules has an overall dipole or not. Put a tick in the correct column for $\text{BCl}_3$, $\text{PCl}_3$, $\text{CCl}_4$ and $\text{SF}_6$.

(c)

Boron and silicon are the two elements beside carbon in the periodic table. $\text{CCl}_4$ does not react with water, but $\text{BCl}_3$ and $\text{SiCl}_4$ do react.

(c(i))

Suggest a reason for this difference in reactivity.

(c(ii))[3]

Construct equations to show how these two chlorides react with an excess of water: $\text{BCl}_3$ and $\text{SiCl}_4$.

(d)

When $\text{SiCl}_4$ reacts with a small amount of water, it forms an oxychloride $X$, $\text{Si}_x\text{Cl}_y\text{O}_z$. The mass spectrum of $X$ contains peaks at mass numbers 133, 149, 247, 263 and 396. (You should assume that the species responsible for all these peaks contain only the $^{16}\text{O}$, the $^{35}\text{Cl}$ and the $^{28}\text{Si}$ isotopes.)

(d(i))

Use these data to deduce the molecular formula of $X$.

(d(ii))

Suggest the structures of the fragments responsible for the peaks at the following mass numbers: 133, 247 and 263.

(d(iii))[5]

Hence suggest the displayed formula of $X$.

Worked solution & mark scheme

This 11-mark question has a full step-by-step worked solution and mark scheme. One marking point: $\mathrm{SiF_4}$ is tetrahedral and symmetrical, so the dipoles cancel

  • Full mark scheme, point by point
  • Step-by-step worked solution
  • Write your answer & get it marked instantly by AI