Chemistry 9701 · AS & A Level · States of matter

States of matter — practice question

(a)[1]

Fluorine is much more electronegative than both silicon and sulfur, yet $\text{SF}_4$ has an overall dipole whereas $\text{SiF}_4$ does not. Suggest a reason for this difference.

(b)[2]

Predict whether each of the following molecules will or will not have an overall dipole. Put a tick in the appropriate column for $\text{BCl}_3$, $\text{PCl}_3$, $\text{CCl}_4$ and $\text{SF}_6$.

(c)

Boron and silicon are two elements next to carbon in the periodic table. $\text{CCl}_4$ does not react with water, but $\text{BCl}_3$ and $\text{SiCl}_4$ do.

(c(i))

Suggest a reason for this difference in reactivity.

(c(ii))[3]

Construct equations to show the reaction of these two chlorides with excess water, for $\text{BCl}_3$ and for $\text{SiCl}_4$.

(d)

When $\text{SiCl}_4$ reacts with a small quantity of water, it forms an oxychloride $X$, $\text{Si}_2\text{Cl}_6\text{O}$. The mass spectrum of $X$ contains peaks at mass numbers of $133$, $149$, $247$, $263$ and $396$. (Assume that the species giving all of these peaks contain only the $^{16}\text{O}$, $^{35}\text{Cl}$ and $^{28}\text{Si}$ isotopes.)

(d(i))

Use these data to deduce the molecular formula of $X$.

(d(ii))

Suggest the structures of the fragments responsible for the peaks at the following mass numbers: $133$, $247$ and $263$.

(d(iii))[5]

Hence suggest the displayed formula for $X$.

Worked solution & mark scheme

This 11-mark question has a full step-by-step worked solution and mark scheme. One marking point: $SiF_4$ is tetrahedral and symmetrical, so the dipoles cancel out

  • Full mark scheme, point by point
  • Step-by-step worked solution
  • Write your answer & get it marked instantly by AI