When $\text{ClNO}_2$ reacts with $\text{NO}$, an equilibrium is set up:
$\text{ClNO}_2\text{(g)} + \text{NO(g)} \rightleftharpoons \text{NO}_2\text{(g)} + \text{ClNO(g)}$
In every $\text{ClNO}_2$ molecule, the nitrogen atom is connected to the chlorine atom and to each oxygen atom separately.
(a)[2]
Draw a ‘dot-and-cross’ diagram of the $\text{ClNO}_2$ molecule.
(b(i))[1]
Write down the rate equation for this reaction.
(b(ii))[1]
Deduce the units of the rate constant, $k$, when the concentrations of both gases are given in $\text{mol dm}^{-3}$ and the rate is measured in $\text{mol dm}^{-3}\text{s}^{-1}$.
(b(iii))[1]
State and explain whether the reaction could occur in a single step or not.
(c(i))[2]
Draw a graph on the grid to show how the concentration of $\text{ClNO}_2$ changes during the first $0.20\ \text{s}$.
(c(ii))[1]
Deduce the concentration of the $\text{NO}_2$ product when $0.20\ \text{s}$ has elapsed.
(c(iii))[1]
After $20\ \text{s}$ the concentration of $\text{ClNO}_2$ stays constant. Explain this observation.
Worked solution & mark scheme
This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: “N atom has eight electrons around it with $\text{N}=\text{O}$, N-O, N-Cl, with N-O shown as dative” …