A tertiary bromoalkane, shown here by $>\!\text{C-Br}$, is reacted with aqueous NaOH. The reaction route is given in the mechanism diagram below. Which point in the diagram is labelled correctly?
- AX is $>\!\text{C}^+$
- BX is $[\text{HO}-\text{C}-\text{Br}]^-$
- CY is $>\!\text{C}^+$
- DY is $[\text{HO}-\text{C}-\text{Br}]^-$