Butanoic acid may be made from 1-bromopropane in two steps by using reagents V and W, as indicated below. $\text{1-bromopropane} \xrightarrow{\text{reagent V}} \text{compound Q} \xrightarrow{\text{reagent W}} \text{butanoic acid}$ What could be reagents V and W?
- AV: KCN in ethanol; W: HCl(aq)
- BV: KCN in ethanol; W: NaOH(aq)
- CV: $\text{NH}_3$ in ethanol; W: HCl(aq)
- DV: NaOH(aq); W: $\text{H}^+/\text{Cr}_2\text{O}_7^{2-}$(aq)