Compound L has the empirical formula NH. When it is gently heated, it breaks down to form only ammonia and compound M. An aqueous solution of compound L conducts electricity well. Which row might be correct?
- Aidentity of M: $\text{N}_2\text{H}_4$; species present in $\text{L(aq)}$: $\text{N}^{3-}$ and $\text{H}^+$
- Bidentity of M: $\text{N}_2\text{H}_4$; species present in $\text{L(aq)}$: $\text{NH}_4^+$ and $\text{NH}_2^-$
- Cidentity of M: $\text{HN}_3$; species present in $\text{L(aq)}$: $\text{NH}_3$ and $\text{HN}_3$
- Didentity of M: $\text{HN}_3$; species present in $\text{L(aq)}$: $\text{NH}_4^+$ and $\text{N}_3^-$