Chemistry 9701 · AS & A Level · Hydrocarbons

Hydrocarbons — practice question

The aromatic molecule benzene has formula $\text{C}_6\text{H}_6$.
(a)[1]

State the $\text{C--C--C}$ bond angle and the hybridisation of the carbon atoms in benzene.

(b(i))[1]

The first stage is the formation of the $^+\text{CH}_2\text{CH}_3$ electrophile. Give an equation that produces this electrophile.

(b(ii))[3]

Describe the mechanism for the reaction of benzene with the $^+\text{CH}_2\text{CH}_3$ electrophile. Show all the relevant curly arrows and charges.

(c(i))[1]

Identify a suitable reagent that can be used to show this difference in reactivity. The reagent selected should give visibly different outcomes with chlorobenzene and chloroethane.

(c(ii))[1]

Write equations for any reactions that occur.

(c(iii))[1]

Explain why chlorobenzene and chloroethane differ in reactivity in nucleophilic substitution reactions.

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: Angle: $120^\circ$; hybridisation: $sp^2$.

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