Alkane S has the molecular formula $\text{C}_4\text{H}_{10}$. In sunlight, S reacts with $\text{Cl}_2(g)$ to form just two distinct monochloroalkanes, $\text{C}_4\text{H}_9\text{Cl}$. Each of these monochloroalkanes is then heated with ethanolic $\text{KOH}$. In both cases, the same alkene T is formed, with no additional organic products. What is formed when T is reacted with hot concentrated acidified $\text{KMnO}_4$?
- A$\text{CO}_2$ and $\text{CH}_3\text{CH}_2\text{CO}_2\text{H}$
- B$\text{CO}_2$ and $\text{CH}_3\text{COCH}_3$
- C$\text{HCO}_2\text{H}$ and $\text{CH}_3\text{COCH}_3$
- D$\text{CH}_3\text{CO}_2\text{H}$ only