Name the reaction type shown.
Name the catalyst used and state the conditions required for this reaction to happen.
Fill in the table to indicate how many sigma ($\sigma$) bonds and pi ($\pi$) bonds are in propene, $\text{C}_3\text{H}_6$, and $\text{C}_3\text{H}_8\text{O}$.
The reaction of propene, $\text{C}_3\text{H}_6$, with $\text{H}_2\text{O}$ takes place by a two-step mechanism. In step 1, $\text{C}_3\text{H}_6$ reacts with the catalyst, $\text{H}^+$, to produce a carbocation. Draw structures to show the more stable and less stable carbocations that can form in step 1. Explain your answer.
Name the principal organic product formed from the reaction of propene, $\text{C}_3\text{H}_6$, with $\text{H}_2\text{O}$.
Under suitable conditions, 2-bromopropane is converted into propene, hydrogen bromide and water. Name this type of reaction.
State the reagents and conditions that favour this reaction. reagents … conditions …