Alkane X has the molecular formula $\text{C}_4\text{H}_{10}$. In sunlight, X reacts with $\text{Cl}_2(g)$ to form only two distinct monochloroalkanes, $\text{C}_4\text{H}_9\text{Cl}$. When each of these monochloroalkanes is heated with ethanolic KOH, the same alkene Y is obtained, and no other organic products are formed. What is formed when Y is treated with hot concentrated acidified $\text{KMnO}_4$?
- A$\text{CO}_2$ and $\text{CH}_3\text{CH}_2\text{CO}_2\text{H}$
- B$\text{CO}_2$ and $\text{CH}_3\text{COCH}_3$
- C$\text{HCO}_2\text{H}$ and $\text{CH}_3\text{COCH}_3$
- D$\text{CH}_3\text{CO}_2\text{H}$ only