Isomers X and Y each react with HBr. A blend of X and Y is then treated with HBr. Which three structures are the three different possible products formed in this reaction?
- A$(\text{CH}_3)_2\text{CHCBr}_3$, $(\text{CH}_3)_2\text{CBrCHBr}_2$, $\text{CH}_3\text{CHBrCHBrCH}_3$
- B$(\text{CH}_3)_2\text{CHCBr}_3$, $(\text{CH}_3)_2\text{CBrCHBr}_2$, $\text{CH}_3\text{CBr}_2\text{CHBrCH}_3$
- C$(\text{CH}_3)_2\text{CBrCBr}_3$, $(\text{CH}_3)_2\text{CHCBr}_3$, $\text{CH}_3\text{CBr}_2\text{CHBrCH}_3$
- D$(\text{CH}_3)_2\text{CBrCHBr}_2$, $\text{CHBr}_2\text{CBr(CH}_3)\text{CH}_3$, $\text{CH}_3\text{CHBrCBr}_2\text{CH}_3$