Dibromopentanes are able to undergo ‘double elimination’ reactions, forming hydrocarbons. $\text{2NaOH} + \text{C}_5\text{H}_{10}\text{Br}_2 \rightarrow \text{C}_5\text{H}_8 + \text{2NaBr} + \text{2H}_2\text{O}$ Which isomer gives just one hydrocarbon product?
- A1,5-dibromopentane
- B1,4-dibromopentane
- C2,3-dibromopentane
- D2,4-dibromopentane