Describe the lattice arrangement in solid $\text{C}_{60}$.
$\text{C}_{60}$ sublimes (changes straight from solid to gas) at about $800\,\text{K}$. Diamond also sublimes, but only above $3800\,\text{K}$. Explain why $\text{C}_{60}$ and diamond sublime at such different temperatures.
$\text{C}_{60}$ forms hydrocarbons with similar chemical properties to those of alkenes. One such hydrocarbon is $\text{C}_{60}\text{H}_{18}$. State what the term hydrocarbon means.
Describe a test to show the presence of double bonds between carbon atoms in $\text{C}_{60}\text{H}_{18}$. Give the result of the test.
Name the type of reaction that occurred.
Calculate the amount, in moles, of $\text{C}_{60}$ that reacted.
Calculate the amount, in moles, of hydrogen gas that reacted with the $\text{C}_{60}$.
Use your answers from (ii) and (iii) to deduce the molecular formula of the hydrocarbon, $\text{C}_{60}\text{H}_{2x}$. If you could not work out the amount of hydrogen gas, take $0.00240\ \text{mol}$ of hydrogen gas as the value reacted. This is not the correct amount of hydrogen gas that reacted.
State the type of bonding and structure shown by silicon.
When silicon reacts with magnesium, $\text{Mg}_2\text{Si}$ is formed. $\text{Mg}_2\text{Si}$ is believed to contain the $\text{Si}^{4-}$ ion. State the full electronic configuration of the $\text{Si}^{4-}$ ion.
Solid $\text{Mg}_2\text{Si}$ reacts with dilute hydrochloric acid to make gaseous $\text{SiH}_4$ and a solution of magnesium chloride. Write an equation for the reaction of solid $\text{Mg}_2\text{Si}$ with dilute hydrochloric acid. Include state symbols.
Predict the shape of the $\text{SiH}_4$ molecule.
$\text{SiH}_4$ reacts spontaneously with oxygen to form a white solid and a colourless liquid that turns anhydrous copper(II) sulfate blue. No other products are made. Write an equation for the reaction of $\text{SiH}_4$ with oxygen. State symbols are not required.