A tertiary bromoalkane, represented here by $>\!\text{C--Br}$, undergoes reaction with aqueous $\text{NaOH}$. The mechanism follows the pathway illustrated. Which point on the diagram is labelled correctly?
- AX is $>\!\text{C}^+$
- BX is $[\text{HO--}\!\text{C}\cdots\text{Br}]^-$
- CY is $>\!\text{C}^+$
- DY is $[\text{HO--}\!\text{C}\cdots\text{Br}]^-$