Chemistry 9701 · AS & A Level · Group 17

Group 17 — practice question

Hydrogen iodide, HI, is a colourless gas at room temperature.
(a(i))[2]

Explain why HI has a higher boiling point than HCl and HBr.

(a(ii))[2]

The bar chart gives the boiling points of HCl, HBr and HI. The boiling point of HF is not included. Hydrogen bonds are formed between HF molecules. Draw a bar on the bar chart to predict the boiling point of HF. Explain your answer.

(b)[2]

The standard enthalpy change of formation, $\Delta H_f^{\circ}$, of $\text{HI}(g)$ is $+26.5\,\text{kJ mol}^{-1}$. Define the term standard enthalpy change of formation.

(c(i))[1]

$\text{HI}(g)$ can be made by reacting $\text{H}_2(g)$ with $\text{I}_2(g)$. The reaction is reversible, and at high temperatures equilibrium is reached rapidly. $\text{H}_2(g) + \text{I}_2(g) \rightleftharpoons 2\text{HI}(g)$. Construct an expression for the equilibrium constant, $K_p$, for the reaction of $\text{H}_2(g)$ and $\text{I}_2(g)$ to form $\text{HI}(g)$.

(c(ii))[1]

The equilibrium partial pressures of the gases at $200^{\circ}\text{C}$ are as follows: $p_{\text{H}_2(g)} = 895\,\text{Pa}$, $p_{\text{I}_2(g)} = 895\,\text{Pa}$, $p_{\text{HI}(g)} = 4800\,\text{Pa}$. Calculate $K_p$ for this reaction.

(c(iii))[2]

State how the value of $K_p$ would change, if at all, if the reaction were carried out at $100^{\circ}\text{C}$ rather than $200^{\circ}\text{C}$. Explain your answer.

(d(i))[1]

HI reacts with oxygen to form iodine and water. Construct an equation for the reaction of HI with oxygen.

(d(ii))[2]

Explain, with reference to oxidation numbers, why this reaction is a redox reaction.

(e)[2]

$\text{HI}(g)$ can also be made by reacting $\text{I}_2(g)$ with hydrazine, $\text{N}_2\text{H}_4(g)$. $2\text{I}_2(g) + \text{N}_2\text{H}_4(g) \rightarrow 4\text{HI}(g) + \text{N}_2(g)$. State the change in pressure that would occur when $2\,\text{mol}$ $\text{I}_2(g)$ fully reacts with $1\,\text{mol}$ $\text{N}_2\text{H}_4(g)$ in a sealed container at constant temperature. Explain your answer.

(f(i))[2]

In the laboratory, HI(aq) can be formed in a two-step process. step 1: $\text{3I}_2$(s) $+$ $\text{2P}$(s) $\rightarrow$ $\text{2PI}_3$(s) step 2: $\text{PI}_3$(s) $+$ $\text{3H}_2\text{O}$(l) $\rightarrow$ $\text{H}_3\text{PO}_3$(aq) $+$ $\text{3HI}$(aq) Draw a ‘dot-and-cross’ diagram of a $\text{PI}_3$ molecule.

(f(ii))[1]

Name the type of reaction in step 2.

(f(iii))[2]

$\text{H}_3\text{PO}_3$(aq) and $\text{HI}$(aq) are both strong Brønsted-Lowry acids. Give the meaning of the term strong Brønsted-Lowry acid.

(f(iv))[1]

Give the formula of the conjugate base of $\text{H}_3\text{PO}_3$.

(g(i))[2]

HI(g) reacts with propene, $\text{CH}_3\text{CH}=\text{CH}_2$(g), to form a mixture of 1-iodopropane and 2-iodopropane. Identify which of 1-iodopropane and 2-iodopropane is the major product of this reaction. Explain your answer.

(g(ii))[3]

Complete the diagram to show the mechanism of the reaction between HI and $\text{CH}_3\text{CH}=\text{CH}_2$ that forms the major product identified in (g)(i). Include curly arrows, lone pairs of electrons and charges as necessary.

Worked solution & mark scheme

This 26-mark question has a full step-by-step worked solution and mark scheme. One marking point: HI / I / iodine / hydrogen iodide has more electrons

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