$\text{ICl}$ forms when $\text{Cl}_2$ and $\text{I}_2$ react with each other. $\text{Cl}_2 + \text{I}_2 \rightleftharpoons 2\text{ICl}$ $\text{ICl}$ then reacts in water. $5\text{ICl} + 3\text{H}_2\text{O} \rightarrow 5\text{HCl} + \text{HIO}_3 + 2\text{I}_2$ Which row is right?
- Aoxidation number of I in ICl: $+1$; the iodine atoms are oxidised to form $\text{I}_2$
- Boxidation number of I in ICl: $+1$; the iodine atoms are oxidised to form $\text{HIO}_3$
- Coxidation number of I in ICl: $-1$; the chlorine atoms are reduced to form $\text{HCl}$
- Doxidation number of I in ICl: $-1$; the iodine atoms are oxidised to form $\text{HIO}_3$