Chemistry 9701 · AS & A Level · Group 17

Group 17 — practice question

At room temperature, concentrated sulfuric acid reacts with sodium halide salts.
(a(i))[1]

Write an equation that represents the reaction of $\text{NaCl}(s)$ with concentrated sulfuric acid.

(a(ii))[1]

Give the name of this reaction type.

(b(i))[1]

At room temperature, $\text{NaI}(s)$ reacts with concentrated sulfuric acid and gives steamy fumes. Identify the substance responsible for those fumes.

(b(ii))[2]

As the reaction of $\text{NaI}(s)$ with concentrated sulfuric acid continues, several more products are formed, including a dark grey solid. Identify the chemical that produces the dark grey solid and name one other product from this further reaction.

(c)[2]

Explain why the observations at room temperature are different when $\text{NaI}(s)$ reacts with concentrated sulfuric acid compared with $\text{NaCl}(s)$.

(d)[1]

Complete the equation for the reaction between $\text{Br}^-$ and excess concentrated $\text{H}_2\text{SO}_4$ at room temperature. $\ldots \text{Br}^- + \ldots \text{H}^+ + \ldots \text{H}_2\text{SO}_4 \rightarrow \ldots$

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: Either $\mathrm{NaCl + H_2SO_4 \rightarrow NaHSO_4 + HCl}$ OR $\mathrm{2NaCl + H_2SO_4 \rightarrow Na_2SO_4 + 2HCl}$

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