Chemistry 9701 · AS & A Level · Group 17

Group 17 — practice question

The equation shown in part (a)(i) represents the reaction that takes place when aqueous potassium iodide is added to aqueous copper(II) sulfate. A white precipitate of copper(I) iodide is produced in a brown solution of iodine and potassium sulfate.
(a(i))[2]

Balance the equation and show state symbols: $\text{CuSO}_4(\,) + \text{KI}(\,) \rightarrow \text{CuI}(\,) + \text{I}_2(\,) + \text{K}_2\text{SO}_4(\,)$

(a(ii))[1]

Deduce the oxidation number of copper in $\text{CuSO}_4$ and $\text{CuI}$.

(a(iii))[2]

Describe the type of reaction shown by the equation in part (a)(i). Explain your answer in terms of electron transfer.

(b)[4]

In the reaction described in part (a)(i), a student uses $17.43\,\text{g}$ of $\text{CuSO}_4\cdot y\text{H}_2\text{O}$. After further titration of the reaction products, the student finds that the total amount of $\text{CuSO}_4$ in the sample is $0.0982\,\text{mol}$. Use the Data Booklet to complete the table and calculate the value of $y$, where $y$ is an integer. Show your working.

Worked solution & mark scheme

This 9-mark question has a full step-by-step worked solution and mark scheme. One marking point: Equation correctly balanced $2CuSO_4(aq) + 4KI(aq) \rightarrow 2CuI(s) + I_2(aq) + 2K_2SO_4(aq)$

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