When lithium is exposed to nitrogen at room temperature, solid $\text{Li}_3\text{N}$ is produced. As shown, three vessels with the same volume are joined by taps 1 and 2. In the central vessel, the equilibrium reaction is $\text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) \rightleftharpoons 2\text{NH}_3(\text{g})$. Initially, taps 1 and 2 are shut, the left-hand vessel has been evacuated, the middle vessel contains the reaction mixture at equilibrium and the right-hand vessel contains lithium only. Which action would cause the equilibrium mixture to contain the maximum amount of ammonia?
- AKeep taps 1 and 2 closed.
- BOpen both taps 1 and 2.
- COpen tap 1 only.
- DOpen tap 2 only.