Industrially, ethanol is made by allowing ethene to react with steam. $\text{C}_2\text{H}_4\text{(g)} + \text{H}_2\text{O(g)} \rightleftharpoons \text{C}_2\text{H}_5\text{OH(g)}$ The value of $K_p$ is $1.8 \times 10^{-5}$, and the equilibrium partial pressures of the reactants are given below. Ethene: $4.8 \times 10^3\,\text{kPa}$ Steam: $2.8 \times 10^3\,\text{kPa}$ Which row gives the correct answer?
- Apartial pressure of ethanol $= 2.42 \times 10^2\,\text{kPa}$, units of $K_p = \text{kPa}^{-1}$
- Bpartial pressure of ethanol $= 2.42 \times 10^2\,\text{kPa}$, units of $K_p = \text{kPa}$
- Cpartial pressure of ethanol $= 7.47 \times 10^{11}\,\text{kPa}$, units of $K_p = \text{kPa}^{-1}$
- Dpartial pressure of ethanol $= 7.47 \times 10^{11}\,\text{kPa}$, units of $K_p = \text{kPa}$