Chemistry 9701 · AS & A Level · Equilibria

Equilibria — practice question

(a)[1]

Write an expression for the $K_a$ of the weak acid HA using the concentrations of the species present.

(b(i))[2]

The hydroxylammonium ion, $\\text{HONH}_3^+$, behaves as a weak acid. A $1.00 \\times 10^{-3}\\,\\text{mol dm}^{-3}$ solution of hydroxylammonium ions has a pH of $4.41$. Calculate the $K_a$ of $\\text{HONH}_3^+$.

(b(ii))[1]

Calculate the $\\text{p}K_a$ value for $\\text{HONH}_3^+$.

(c)[2]

The solubility product of manganese(II) hydroxide, $\\text{Mn(OH)}_2$, in water is $1.1 \\times 10^{-11}\\,\\text{mol}^3\\,\\text{dm}^{-9}$ at $298\\,\\text{K}$. Calculate the solubility of $\\text{Mn(OH)}_2$ in water at $298\\,\\text{K}$.

Worked solution & mark scheme

This 6-mark question has a full step-by-step worked solution and mark scheme. One marking point: The required expression is $\\frac{[\\text{H}^+][\\text{A}^-]}{[\\text{HA}]}$.

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