Chemistry 9701 · AS & A Level · Equilibria

Equilibria — practice question

In biological cells, the phosphate buffer system is at work. The buffer includes dihydrogen phosphate, $\text{H}_2\text{PO}_4^{-}$, which behaves as a weak acid. $\text{H}_2\text{PO}_4^{-} + \text{H}_2\text{O} \rightleftharpoons \text{HPO}_4^{2-} + \text{H}_3\text{O}^{+}$
(a)[1]

Write the $K_a$ expression for $\text{H}_2\text{PO}_4^{-}$.

(b(i))[2]

Explain what the term buffer solution means.

(b(ii))[2]

Write two equations to demonstrate how a mixture of $\text{H}_2\text{PO}_4^{-}$ and $\text{HPO}_4^{2-}$ functions as a buffer.

(c)[3]

Calculate the value of $[\text{HPO}_4^{2-}]/[\text{H}_2\text{PO}_4^{-}]$ needed to produce a pH of $7.40$ in the cells, given that $K_a = 6.31 \times 10^{-8}\,\text{mol dm}^{-3}$.

(d(i))[1]

Write an equation to show $\text{H}_2\text{PO}_4^{-}$ acting as a base.

(d(ii))[1]

Write an equation to show $\text{HPO}_4^{2-}$ acting as an acid.

Worked solution & mark scheme

This 10-mark question has a full step-by-step worked solution and mark scheme. One marking point: Hence, $K_a = \frac{[HPO_4^{2-}][H_3O^+]}{[H_2PO_4^-]}$.

  • Full mark scheme, point by point
  • Step-by-step worked solution
  • Write your answer & get it marked instantly by AI