Chemistry 9701 · AS & A Level · Electrochemistry

Electrochemistry — practice question

The term ‘chlorate’ describes an anion containing only chlorine and oxygen. In a molecule of $\text{ICl}$, the iodine atom has oxidation number $x$ and the chlorine atom has oxidation number $y$. When $\text{ICl}$ is mixed with $\text{H}_2\text{O}$, the iodine is reduced. $4\text{ICl} + 2\text{H}_2\text{O} \rightarrow 4\text{HCl} + \text{O}_2 + 2\text{I}_2$ Which statement correctly gives the value of $x$ or $y$?

  • A$x$ is the same as the oxidation number of Cl in the chlorate ion formed when $\text{Cl}_2\text{(aq)}$ is added to cold $\text{NaOH}\text{(aq)}$.
  • B$x$ is the same as the oxidation number of Cl in the chlorate ion formed when $\text{Cl}_2\text{(aq)}$ is added to hot $\text{NaOH}\text{(aq)}$.
  • C$y$ is the same as the oxidation number of Cl in the chlorate ion formed when $\text{Cl}_2\text{(aq)}$ is added to cold $\text{NaOH}\text{(aq)}$.
  • D$y$ is the same as the oxidation number of Cl in the chlorate ion formed when $\text{Cl}_2\text{(aq)}$ is added to hot $\text{NaOH}\text{(aq)}$.

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