The reaction of KI with concentrated $\text{H}_2\text{SO}_4$ is a redox reaction. $\text{5H}_2\text{SO}_4 + \text{8KI} \rightarrow \text{4K}_2\text{SO}_4 + \text{4I}_2 + \text{H}_2\text{S} + \text{4H}_2\text{O}$. By how much does the oxidation state change for the element that is reduced?
- A$1$
- B$4$
- C$6$
- D$8$