The Data Booklet may be needed for this question. Lead(IV) chloride oxidises bromide ions to bromine. In this reaction, the $\text{Pb}^{4+}$ ions are reduced to $\text{Pb}^{2+}$ ions. If $6.980\,\text{g}$ of lead(IV) chloride is added to an excess of sodium bromide solution, what mass of bromine would be formed?
- A$0.799\,\text{g}$
- B$1.598\,\text{g}$
- C$3.196\,\text{g}$
- D$6.392\,\text{g}$