$W$ moles of $\text{HNO}_2$ is subjected to a disproportionation reaction, giving $U$ moles of $\text{HNO}_3$ and $V$ moles of $\text{NO}$. No other product containing nitrogen is formed. Nitrogen is the only element that is oxidised or reduced. What are the values of $W$, $U$ and $V$?
- A$W=2,\;U=1,\;V=1$
- B$W=3,\;U=1,\;V=2$
- C$W=5,\;U=3,\;V=2$
- D$W=5,\;U=1,\;V=4$