Solid sodium chloride and solid sodium iodide each react with concentrated sulfuric acid at room temperature. For $\text{NaCl}$, the products formed are $\text{NaHSO}_4$ and $\text{HCl}$. For $\text{NaI}$, the products are $\text{NaHSO}_4$, $\text{HI}$, $\text{I}_2$, $\text{SO}_2$, $\text{H}_2\text{O}$, $\text{S}$ and $\text{H}_2\text{S}$. What explains the difference between these products?
- AChloride ions will displace iodide ions from solution.
- BHydrogen chloride is more volatile than hydrogen iodide.
- CIodide ions are better reducing agents than chloride ions.
- DSulfuric acid is able to act as a dehydrating agent with NaI.