Use oxidation numbers to answer this question. A redox reaction occurs between hydroxylammonium ions, $[\text{NH}_3\text{OH}]^+$, and acidified iron(III) ions, $\text{Fe}^{3+}$. The products are iron(II) ions, $\text{Fe}^{2+}$, $\text{H}^+$ ions, water, and a nitrogen compound. The mole ratio of hydroxylammonium ions reacting to iron(III) ions reacting is $1:2$. Which nitrogen-containing compound could be produced in the reaction?
- A$\text{NH}_3$
- B$\text{N}_2\text{O}$
- C$\text{NO}$
- D$\text{NO}_2$