When ethanedioate ions, $\text{C}_2\text{O}_4^{2-}$, react with an appropriate reagent, $\text{CO}_2$ is produced. The half-equation for this reaction is given below. $\text{C}_2\text{O}_4^{2-} \rightarrow 2\text{CO}_2 + 2e^-$ Which row is the correct one?
- Aoxidation state of carbon in $\text{C}_2\text{O}_4^{2-}$: $+3$; type of reaction: oxidation
- Boxidation state of carbon in $\text{C}_2\text{O}_4^{2-}$: $+3$; type of reaction: reduction
- Coxidation state of carbon in $\text{C}_2\text{O}_4^{2-}$: $+5$; type of reaction: oxidation
- Doxidation state of carbon in $\text{C}_2\text{O}_4^{2-}$: $+5$; type of reaction: reduction