$\text{VO}_2\text{Cl}$ reacts with NaI in acidic conditions. $2\text{VO}_2\text{Cl} + 2\text{H}_2\text{SO}_4 + 2\text{NaI} \rightarrow \text{VOCl}_2 + \text{VOSO}_4 + \text{I}_2 + \text{Na}_2\text{SO}_4 + 2\text{H}_2\text{O}$ The oxidation state of Cl is $-1$ in $\text{VO}_2\text{Cl}$ and in $\text{VOCl}_2$. Which row describing this reaction is correct?
- Avanadium is oxidised; iodine is oxidised
- Bvanadium is oxidised; iodine is reduced
- Cvanadium is reduced; iodine is oxidised
- Dvanadium is reduced; iodine is reduced