In acidic solution, potassium manganate(VII) is reacted with iron(II) ethanedioate, $\text{FeC}_2\text{O}_4$. The half-equations involved are shown below. $\text{MnO}_4^- + 8\text{H}^+ + 5\text{e}^- \rightarrow \text{Mn}^{2+} + 4\text{H}_2\text{O}$ $\text{Fe}^{2+} \rightarrow \text{Fe}^{3+} + \text{e}^-$ $\text{C}_2\text{O}_4^{2-} \rightarrow 2\text{CO}_2 + 2\text{e}^-$ How many moles of iron(II) ethanedioate are required to react with 1 mole of potassium manganate(VII)?
- A0.60
- B1.67
- C2.50
- D5.00