Chemistry 9701 · AS & A Level · Chemistry of transition elements

Chemistry of transition elements — practice question

(a)[2]

Complete the table by giving the total number of unpaired electrons in the $3d$ and $4s$ orbitals for each isolated gaseous atom: $\text{Cr}$, $\text{Mn}$ and $\text{Fe}$.

(b)[2]

On heating, solid potassium manganate(VII), $\text{KMnO}_4$, breaks down to manganese(IV) oxide, potassium manganate(VI) and a colourless gas. Write an equation for this reaction.

(c)[3]

Explain where the colour in transition element complexes comes from.

(d(i))[3]

Give the formulae of precipitate A, complex ion B and compound C shown in the reaction scheme of $[\text{Cu(H}_2\text{O)}_6]^{2+}$.

(d(ii))[1]

Name a suitable reagent for reaction 3.

(d(iii))[1]

Give an equation for reaction 4.

(d(iv))[1]

State two visual observations that occur during reaction 4.

(e)[1]

Platin, $\text{Pt(NH}_3)_2\text{Cl}_2$, is a neutral platinum(II) complex. Explain why $\text{Pt(NH}_3)_2\text{Cl}_2$ carries no charge.

(f(i))[2]

$\text{Pt(NH}_3)_2\text{Cl}_2$ shows cis-trans isomerism. Draw the structure of trans-platin. State its shape and the $\text{Cl-Pt-Cl}$ bond angle.

(f(ii))[2]

Cis-platin is an effective anti-cancer drug. Describe how cis-platin works in this role.

(g)[1]

Because cis-platin can produce side effects, nedaplatin has been developed. Nedaplatin can be made from cis-platin, $\text{Pt(NH}_3)_2\text{Cl}_2$, by substituting the two chloride ion ligands with one bidentate ligand, as shown. Suggest the structure for nedaplatin.

Worked solution & mark scheme

This 19-mark question has a full step-by-step worked solution and mark scheme. One marking point: Correct count of unpaired electrons in 3d and 4s for Cr, Mn and Fe

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