Chemistry 9701 · AS & A Level · Chemistry of transition elements

Chemistry of transition elements — practice question

(a)[2]

Complete the table to show how many unpaired electrons are present in the $3d$ and $4s$ orbitals of each isolated gaseous atom: Cr, Mn and Fe.

(b)[2]

On heating, solid potassium manganate(VII), $\text{KMnO}_4$, breaks down to give manganese(IV) oxide, potassium manganate(VI) and a colourless gas. Construct an equation for this reaction.

(c)[3]

Explain why transition element complexes are coloured.

(d(i))[3]

The reaction scheme shows several reactions of $[\text{Cu(H}_2\text{O)}_6]^{2+}$. Write the formulae of precipitate A, complex ion B and compound C.

(d(ii))[1]

Identify a reagent suitable for reaction 3.

(d(iii))[1]

Write the equation for reaction 4.

(d(iv))[1]

Describe two visual observations seen during reaction 4.

(e)[1]

Platin, $\text{Pt(NH}_3)_2\text{Cl}_2$, is a neutral platinum(II) complex. Explain why $\text{Pt(NH}_3)_2\text{Cl}_2$ carries no charge.

(f(i))[2]

$\text{Pt(NH}_3)_2\text{Cl}_2$ shows cis-trans isomerism. Draw the structure of trans-platin. State its shape and the Cl-Pt-Cl bond angle.

(f(ii))[2]

Cis-platin is an effective anti-cancer drug. Describe how cis-platin acts in this role.

(g)[1]

Because cis-platin can cause side effects, nedaplatin has been developed. Nedaplatin can be made from cis-platin, $\text{Pt(NH}_3)_2\text{Cl}_2$, by replacing the two chloride ion ligands with one bidentate ligand as shown. Suggest the structure of nedaplatin.

Worked solution & mark scheme

This 19-mark question has a full step-by-step worked solution and mark scheme. One marking point: Correct numbers of unpaired electrons for Cr, Mn and Fe in the 3d and 4s orbitals

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