Chemistry 9701 · AS & A Level · Chemistry of transition elements

Chemistry of transition elements — practice question

Iron is able to form complex ions with the monodentate ligand CN$^-$.
(a(i))[1]

Complex ion A has one Fe$^{3+}$ ion together with six CN$^-$ ligands. Complex ion B has one Fe$^{2+}$ ion together with six CN$^-$ ligands. State the formulae of these two complex ions. Include the overall charge of each complex ion.

(a(ii))[2]

Explain why a solution containing complex ion A and a solution containing complex ion B do not have the same colour.

(a(iii))[1]

In complex ion A, each CN$^-$ ligand uses its carbon atom to bond to the Fe$^{3+}$ ion. State the type of bonding involved.

(b)[4]

The complex ions do not all have the same geometry. Complex ion A is octahedral. Ag$^+$ ions form a linear complex with ammonia. Ni atoms form a tetrahedral complex with carbon monoxide molecules. In the monodentate carbon monoxide ligand, the carbon atom bonds to the nickel atom. Pd$^{2+}$ ions form a square planar complex with chloride ions. Complete Fig. 6.1 to show the geometry of each of these four ions, using three-dimensional bonds where needed. Mark one bond angle on each complex ion.

Worked solution & mark scheme

This 8-mark question has a full step-by-step worked solution and mark scheme. One marking point: $[\mathrm{Fe(CN)_6}]^{3-}$ and $[\mathrm{Fe(CN)_6}]^{4-}$

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