Chemistry 9701 · AS & A Level · Chemistry of transition elements

Chemistry of transition elements — practice question

Carboplatin and satraplatin are anticancer drugs used instead of cisplatin.
(a(i))[2]

Describe how cisplatin acts as an anticancer drug.

(a(ii))[1]

Suggest the geometry around the platinum centre in the carboplatin complex.

(a(iii))[1]

Suggest why carboplatin does not exhibit cis-trans isomerism.

(a(iv))[1]

Satraplatin is a neutral complex that contains the ligands $\text{CH}_3\text{CO}_2^-$, $\text{C}_6\text{H}_{11}\text{NH}_2$, $\text{Cl}^-$ and $\text{NH}_3$. Deduce the oxidation state of platinum in satraplatin.

(b(i))[1]

Draw the structure for $L$.

(b(ii))[2]

Suggest reagents and conditions for each step in this synthesis. step 1 step 2

(b(iii))[1]

Write the equation for step 2.

(b(iv))[3]

A student looks at a possible route to make $M$ directly from benzene by using $\text{COCl}_2$ with an $\text{AlCl}_3$ catalyst. Benzene first reacts with $\text{COCl}_2$ as shown. reaction 1: $\text{COCl}_2 + \text{AlCl}_3 \rightarrow \text{AlCl}_4^- + \text{Cl}^-\text{C}\equiv\text{O}^+$ reaction 2: $\text{C}_6\text{H}_6 + \text{Cl}^-\text{C}\equiv\text{O}^+ \rightarrow \text{C}_6\text{H}_5\text{COCl} + \text{H}^+$ In Reaction 2, $\text{Cl}^-\text{C}\equiv\text{O}^+$ replaces $\text{H}^+$ on benzene by electrophilic substitution. Suggest a mechanism for reaction 2.

Worked solution & mark scheme

This 12-mark question has a full step-by-step worked solution and mark scheme. One marking point: Cisplatin attaches to DNA bases

  • Full mark scheme, point by point
  • Step-by-step worked solution
  • Write your answer & get it marked instantly by AI