Chemistry 9701 · AS & A Level · Chemical energetics

Chemical energetics — practice question

(a)[2]

Predict and explain the pattern in enthalpy change of hydration for the ions $\text{F}^-$, $\text{Cl}^-$, $\text{Br}^-$ and $\text{I}^-$.

(b(i))[1]

Fig. 2.1 shows an incomplete energy cycle for calcium fluoride, $\text{CaF}_2$. Complete line D. Include state symbols.

(b(ii))[2]

The enthalpy change for process 1 can be worked out from five other enthalpy changes that are not shown in Fig. 2.1. Process 1: $\text{Ca(s)} + \text{F}_2(\text{g}) \rightarrow \text{Ca}^{2+}(\text{g}) + 2\text{F}^-(\text{g})$. Identify these five other enthalpy changes, using either names or symbols.

(b)

Fig. 2.1 shows an incomplete energy cycle for calcium fluoride, $\text{CaF}_2$.

(b(iii))[2]

Define lattice energy, $\Delta H_{\text{latt}}$.

(b(iv))[1]

Complete the expression to give the mathematical relationship between $\Delta H_{\text{latt}}$ of calcium fluoride and the enthalpy changes for processes 1 and 3. $\Delta H_{\text{latt}} =$

(c)[2]

Use data from Table 2.1 to calculate a value for the hydration energy, $\Delta H_{\text{hyd}}$, of fluoride ions, $\text{F}^-\text{(g)}$.

(d)[1]

Define entropy.

(e)[2]

At $298\,\text{K}$, the Gibbs free energy change, $\Delta G$, for the solution of compound T is $+6.00\,\text{kJ mol}^{-1}$. The enthalpy change of solution, $\Delta H_{\text{sol}}$, of compound T is $+30.0\,\text{kJ mol}^{-1}$ at $298\,\text{K}$. Calculate the value of the entropy change, $\Delta S$, for the solution of compound T at $298\,\text{K}$.

(f)[1]

Predict whether compound T becomes more or less soluble as the water is heated from $298\,\text{K}$ to $360\,\text{K}$. Explain your answer.

Worked solution & mark scheme

This 14-mark question has a full step-by-step worked solution and mark scheme. One marking point: The enthalpy change becomes less exothermic down the group

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