The molecular formula of propanone is $\text{C}_3\text{H}_6\text{O}$. The enthalpy change of combustion of hydrogen is $-286\,\text{kJ mol}^{-1}$. The enthalpy change of combustion of carbon is $-394\,\text{kJ mol}^{-1}$. The enthalpy change of combustion of propanone is $-1786\,\text{kJ mol}^{-1}$. From this data, determine the enthalpy change of formation of propanone.
- A$-1106\,\text{kJ mol}^{-1}$
- B$-540\,\text{kJ mol}^{-1}$
- C$-254\,\text{kJ mol}^{-1}$
- D$+1106\,\text{kJ mol}^{-1}$