Titanium is found in nature as the mineral rutile, $\text{TiO}_2$. One way to extract titanium is to heat the rutile with carbon so that reduction occurs. $\text{TiO}_2(s) + 2\text{C}(s) \rightarrow \text{Ti}(s) + 2\text{CO}(g)$ The standard enthalpy changes of formation of $\text{TiO}_2(s)$ and $\text{CO}(g)$ are $-940\,\text{kJ mol}^{-1}$ and $-110\,\text{kJ mol}^{-1}$ respectively. Determine the standard enthalpy change for this reaction.
- A$-830\,\text{kJ mol}^{-1}$
- B$-720\,\text{kJ mol}^{-1}$
- C$+720\,\text{kJ mol}^{-1}$
- D$+830\,\text{kJ mol}^{-1}$