A molecule of an organic compound, P, has three carbon atoms and gives a strong absorption at $1720\,\text{cm}^{-1}$ in its infrared spectrum. P is oxidised using excess hot acidified potassium dichromate(VI), giving the organic product Q. Q gives a strong absorption at $1700\,\text{cm}^{-1}$ and a strong, broad absorption centred at $2800\,\text{cm}^{-1}$ in its infrared spectrum. Identify P.
- Apropanal
- Bpropanone
- Cpropan-1-ol
- Dpropan-2-ol