Ethane-1,2-diol, $\text{HOCH}_2\text{CH}_2\text{OH}$, is allowed to react with an excess of ethanoic acid, $\text{CH}_3\text{CO}_2\text{H}$, in the presence of an acid catalyst. This gives a compound with molecular formula $\text{C}_6\text{H}_{10}\text{O}_4$. What is the structure of this compound?
- A$\text{CH}_3\text{OCOCH}_2\text{CH}_2\text{CO}_2\text{CH}_3$
- B$\text{CH}_3\text{CO}_2\text{CH}_2\text{CH}_2\text{CO}_2\text{CH}_3$
- C$\text{CH}_3\text{CO}_2\text{CH}_2\text{CH}_2\text{OCOCH}_3$
- D$\text{HOCH}_2\text{CH}_2\text{COCH}_2\text{OCOCH}_3$