Hept-4-enal occurs in cow’s milk. $\text{CH}_3\text{CH}_2\text{CH=CHCH}_2\text{CH}_2\text{CHO}$ (hept-4-enal) Which row correctly gives the product obtained when hept-4-enal is reacted with the reducing agent shown?
- A$\text{H}_2 + \text{Ni}$ gives $\text{CH}_3(\text{CH}_2)_5\text{CH}_2\text{OH}$
- B$\text{H}_2 + \text{Ni}$ gives $\text{CH}_3(\text{CH}_2)_5\text{CH}_3$
- C$\text{NaBH}_4$ gives $\text{CH}_3(\text{CH}_2)_5\text{CH}_2\text{OH}$
- D$\text{NaBH}_4$ gives $\text{CH}_3(\text{CH}_2)_5\text{CHO}$