Aluminium carbide, $\text{Al}_4\text{C}_3$, undergoes a rapid reaction with aqueous sodium hydroxide. This reaction forms $\text{NaAlO}_2$ and a hydrocarbon as the two products. Water molecules also take part as reactants. What is the formula of the hydrocarbon?
- A$\text{CH}_4$
- B$\text{C}_2\text{H}_6$
- C$\text{C}_3\text{H}_8$
- D$\text{C}_6\text{H}_{12}$