When zinc is treated with concentrated nitric acid, only three products are formed: zinc nitrate, an oxide of nitrogen and water. $3.0$ moles of zinc react with $8.0$ moles of nitric acid. Zinc nitrate contains $\text{Zn}^{2+}$ ions. What might the formula of the oxide of nitrogen be?
- A$ ext{N}_2 ext{O}$
- B$ ext{NO}$
- C$ ext{N}_2 ext{O}_3$
- D$ ext{NO}_2$