Sodium reacts with $1$ mol of compound Y to form $1$ mol of $\text{H}_2\text{(g)}$. Which compound could Y be?
- A$\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{OH}$
- B$(\text{CH}_3)_3\text{COH}$
- C$\text{CH}_3\text{CH}_2\text{CH}_2\text{CO}_2\text{H}$
- D$\text{CH}_3\text{CH(OH)CO}_2\text{H}$