X is an oxide of a Period 3 element. When X reacts with water, an acidic solution is formed. A solution is made by allowing $0.100\,\text{g}$ of X to react with excess water. The resulting solution was then neutralised exactly by $25.0\,\text{cm}^3$ of $0.100\,\text{mol dm}^{-3}$ sodium hydroxide solution. What could X be?
- A$\text{Al}_2\text{O}_3$
- B$\text{MgO}$
- C$\text{P}_4\text{O}_{10}$
- D$\text{SO}_3$