Lead(IV) chloride can oxidise bromide ions, forming bromine. In this reaction, the $\text{Pb}^{4+}$ ions are reduced to $\text{Pb}^{2+}$ ions. When $6.980\ \text{g}$ of lead(IV) chloride is mixed with an excess of sodium bromide solution, what mass of bromine is formed?
- A$0.799\ \text{g}$
- B$1.598\ \text{g}$
- C$3.196\ \text{g}$
- D$6.392\ \text{g}$