Which combination will react to produce exactly one mole of water?
- A$250\,\text{cm}^3$ of $2.00\,\text{mol dm}^{-3}\,\text{H}_2\text{SO}_4$ with $500\,\text{cm}^3$ of $1.00\,\text{mol dm}^{-3}\,\text{NaOH}$
- B$250\,\text{cm}^3$ of $2.00\,\text{mol dm}^{-3}\,\text{H}_2\text{SO}_4$ with $1000\,\text{cm}^3$ of $1.00\,\text{mol dm}^{-3}\,\text{NaOH}$
- C$500\,\text{cm}^3$ of $2.00\,\text{mol dm}^{-3}\,\text{H}_2\text{SO}_4$ with $500\,\text{cm}^3$ of $1.00\,\text{mol dm}^{-3}\,\text{NaOH}$
- D$500\,\text{cm}^3$ of $2.00\,\text{mol dm}^{-3}\,\text{H}_2\text{SO}_4$ with $1000\,\text{cm}^3$ of $1.00\,\text{mol dm}^{-3}\,\text{NaOH}$